3=-48d^2+24d

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Solution for 3=-48d^2+24d equation: 



3=-48d^2+24d

We move all terms to the left:

3-(-48d^2+24d)=0

We get rid of parentheses

48d^2-24d+3=0

a = 48; b = -24; c = +3;
Δ = b2-4ac
Δ = -242-4·48·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{24}{96}=1/4$

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